If the sum of the interior angles of a regular polygon is $$720^\circ$$ then how many sides does it have?
Sum of all interior angles of a polygon with $$'n'$$ sides = $$(n-2)\times180^\circ$$
Let the number of sides be $$n$$
=> Sum of interior angles =Â $$(n-2)\times180^\circ=720^\circ$$
=Â $$(n-2)=\frac{720^\circ}{180^\circ}=4$$
=> $$n=4+2=6$$
=> Ans - (C)
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