Question 22

If a regular polygon has 6 sides then the measure of its interior angle is greater than the measure of its exterior angle by how many degrees?

Solution

Sum of all interior angles of regular polygon with $$n$$ sides = $$(n-2)\times180^\circ$$

=> Sum of interior angles of a regular hexagon = $$(6-2)\times180^\circ=720^\circ$$

Also, sum of exterior angle of an polygon = $$360^\circ$$

$$\therefore$$ Required difference = $$\frac{(720-360)}{6}$$

= $$\frac{360^\circ}{6}=60^\circ$$

=> Ans - (C)

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