Question 2

How many natural numbers are there between 1000 to 2000, which when divided by 341 leaves remainder 5?

Solution

Number should be in the form of, $$N=\left(341k+5\right)\ \ .\left(where,\ k=0,1,2,3,....\right)$$

So, There are only 3 numbers present between 1000 and 2000 which satisfy the above condition.

These are 1028,1369 and 1710 (when , k=3 , 4 and 5)

A is correct choice.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: