How many natural numbers are there between 1000 to 2000, which when divided by 341 leaves remainder 5?
Number should be in the form of, $$N=\left(341k+5\right)\ \ .\left(where,\ k=0,1,2,3,....\right)$$
So, There are only 3 numbers present between 1000 and 2000 which satisfy the above condition.
These are 1028,1369 and 1710 (when , k=3 , 4 and 5)
A is correct choice.
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