A radio can tune to any station in $$6 \text{ MHz}$$ to $$10 \text{ MHz}$$ band. The value of corresponding wavelength bandwidth will be

We need to find the wavelength bandwidth corresponding to the frequency band 6 MHz to 10 MHz.

The relationship between wavelength and frequency is:

$$\lambda = \dfrac{c}{f}$$

where $$c = 3 \times 10^8 \text{ m/s}$$.

For $$f_1 = 6 \text{ MHz} = 6 \times 10^6 \text{ Hz}$$:

$$\lambda_1 = \dfrac{3 \times 10^8}{6 \times 10^6} = 50 \text{ m}$$

For $$f_2 = 10 \text{ MHz} = 10 \times 10^6 \text{ Hz}$$:

$$\lambda_2 = \dfrac{3 \times 10^8}{10 \times 10^6} = 30 \text{ m}$$

The wavelength bandwidth is:

$$\Delta\lambda = \lambda_1 - \lambda_2 = 50 - 30 = 20 \text{ m}$$

Therefore, the correct answer is Option B.