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18. Two runners run in the same direction along a circular track 3 km in length. The faster runner overtakes the slower every 1 hour. Find the speed of the slower runner, if the faster one completes one length of the track 2 minutes sooner than the other.
18. Two runners run in the same direction along a circular track 3 km in length. The faster runner overtakes the slower every 1 hour. Find the speed of the slower runner, if the faster one completes one length of the track 2 minutes sooner than the other.
(A) 20 kmph
(C) 15 kmph
(B) 18 kmph
(D) 12 kmph
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Answer
15KMPH. Since he overtakes the slower one every 1 hr, faster guy's speed is slower guy's speed (say S) + 3 kmph. For a difference of 2 mins we get the equation: (3/S) - (3/(S+3)) = 2/60. Solving for S, we get S = 15KMPH
