An electron of mass $$m_e$$ and a proton of mass $$m_P$$ are accelerated through the same potential difference. The ratio of the de-Broglie wavelength associated with the electron to that with the proton is:

A

$$\frac{m_p}{m_e}$$

B

1

C

$$\sqrt{\frac{m_p}{m_e}}$$

D

$$\frac{m_e}{m_p}$$