A person bought a horse and a carriage for Rs. 20000. Later, he sold the horse at 20% profit and the carriage at 10% loss. Thus, he gained 2% inthe whole transaction. The cost price of the horse was
cost price of horse and carriage = 20000
assume CP for horse be x
then CP for carriage = 20000 - x
According to the question
$$ x \times \frac{120}{100} + (20000 - x) \times \frac{90}{100} = 20000 \times \frac{102}{100} $$
solving,
1.2x + 0.9(20000 - x) = 20400
x = $$ \frac{2400}{0.3} = 8000 $$
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