4 men and 6 women complete a work in 8 days. 2 men and 9 women also complete in 8 days. The number of days in which 18 women complete the work is :
4 men and 6 women takes same time as 2 men and 9 women
Let m-> man and w-> woman
=> $$(4m + 6w) = (2m + 9w)$$
=> $$2m = 3w$$
Let no. of days in which 18 women complete work = $$x$$
=> $$18w * x = (4m + 6w) * 8$$
=> $$18w * x = (6w + 6w) * 8$$
=> $$x = \frac{12 * 8}{18}$$
=> $$x = \frac{16}{3} = 5\frac{1}{3}$$ days
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