Two plane mirrors $$M_1$$ and $$M_2$$ are at right angle to each other as shown. A point source $$P$$ is placed at $$a$$ and $$2a$$ meter away from $$M_1$$ and $$M_2$$ respectively. The shortest distance between the images thus formed is: (Take $$\sqrt{5} = 2.3$$)

A

$$2.3a$$

B

$$2\sqrt{10}a$$

C

$$4.6a$$

D

$$3a$$