The distance between places U and V is 1008 km. An express train leaves place U at 9:00 a.m. and runs at a speed of 126 km/hr. The train stops on the way for 20 minutes. At what time (in p.m.) the train will reach at the place V?
Distance to be covered = 1008 km and speed of train = 126 km/hr
Using, time = distance/speed
=> Time taken = $$\frac{1008}{126}=8$$ hours
$$\therefore$$ Train will reach at place V = 9:00 am + 8 hours + 20 minutes =Â 5 : 20 pm
=> Ans - (D)
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