When the angle of elevation of the sun increases from 30$$^{\circ}$$ to 60$$^{\circ}$$ , the shadow of a post is diminished by 5 metres. Then the height of the post is
With $$60^o$$ angle, length of shadow will be $$\frac{x}{\sqrt3}$$ (where $$x$$ is length of post)
With $$30^0$$ angle, length of shadow will be $$5+\frac{x}{\sqrt3}$$
or $$tan30^o = \frac{x}{5+\frac{x}{\sqrt3}}$$
After solving above equation, we will get $$x$$ equals to $$\frac{5\sqrt3}{2}$$
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