Question 138

The selling price of 10 oranges is the cost price of 13 oranges. Then the profit percentage is

Solution

Let's say selling price of 10 oranges = cost price of 13 = $$y$$

cost price of 1 will be = $$\frac{y}{13}$$

cost price of 10 will be = $$\frac{10y}{13}$$

Selling price of 10 is =$$ y$$

Gain is =$$\frac{3y}{13}$$ 

Percentage gain = $$\frac{\frac{3y}{13} }{\frac{10y}{13}}\times 100$$=30%


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