Walking at 3/4th of his usual speed , aman is $$1\frac{1}{2}$$ hours late. his usual time to cover the same distance, in hours, is?
As distance is constant
Hence $$v_1 \times t_1 = \frac{3v_1}{4} \times (t_1 + \frac{3}{2})$$ (Where is $$v_1$$ is speed, t_1 is time taken to travel)
On solving above equation, we will get $$t_1 = \frac{9}{2}$$
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