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Question 134
In ΔABC and Δ DEF. AB = DE and BC = EF. Then one can infer that Δ ABC ≅ Δ DEF, when
Solution
AB = DE and BC = EF
Two triangles are congruent if two sides and included angle of one are equal to the corresponding sides and the included angle of the other triangle.(SAS criterion)
Thus, if $$\angle$$ABC = $$\angle$$DEF
Then, $$\triangle ABC \cong \triangle DEF$$
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