Question 134

In ΔABC and Δ DEF. AB = DE and BC = EF. Then one can infer that Δ ABC ≅ Δ DEF, when

Solution

AB = DE and BC = EF

Two triangles are congruent if two sides and included angle of one are equal to the corresponding sides and the included angle of the other triangle.(SAS criterion)

Thus, if $$\angle$$ABC = $$\angle$$DEF

Then, $$\triangle ABC \cong \triangle DEF$$


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