The magnetic moment of a bar magnet is $$0.5$$ Am$$^2$$. It is suspended in a uniform magnetic field of $$8 \times 10^{-2}$$ T. The work done in rotating it from its most stable to most unstable position is:

A

$$8 \times 10^{-2}$$ J

B

$$4 \times 10^{-2}$$ J

C

Zero

D

$$16 \times 10^{-2}$$ J