123123123.....300 digits when divided by 99. what will be the remainder ?

123123123....300 digits = 123(10^297+ 10^294 + 10^291 + ....... + 10^3 + 10^0).
10^odd mod 99 = 10
10^even mod 99 = 1 .
so 123123123... 300 digits mod 99 = 123(10^297 + 10^294 + ...... + 1 ) mod 99
= 24(10 + 1 + 10 + 1 ........+10 + 1) mod 99
(total 50 *10 = 500 and 50 *1 = 50)
= 24(550) mod 99
= 24(55) mod 99
= 33
correct ?

123123.........(40 times ) devided by 3125 leaves remainder of ?

Download Number systems formulas covering Remainder theorems, which will hep for CAT aspirants

yup correct..thanx a lot