SSC CGL 2012 Tier 1 1 July NZ Evening V

Question 120

The three medians AD, BE and CF of triangle ABC intersect at point G. If the area of triangle ABC is 60 sq.cm. then the area of the quadrilateral BDGF is :

Solution

Given ∆ABC, G is the centroid and AD,BE, CF are three medians and the area of ∆AGE = 10
As we know the median divides the triangle into 6 triangles of equal area
Hence area of the quadrilateral BDGF = 2*∆AGE = 2*10
area of the quadrilateral BDGF = 20

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