An equilateral triangle ABC is inscribed in a circle of radius $$20\sqrt{3}$$ cm. What is the length of the side of the triangle?

An equilateral triangle ABC is inscribed in a circle of radius $$20\sqrt{3}$$ cm. Thus, the circumradius of the triangle is $$20\sqrt{3}$$ cm.

Area of triangle = $$\dfrac{abc}{4R}$$

$$\dfrac{\sqrt{3}a^2}{4}=\dfrac{a\times a\times a}{4\times20\sqrt{3}}$$

$$a=60$$ cm

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