A magnet hung at $$45°$$ with magnetic meridian makes an angle of $$60°$$ with the horizontal. The actual value of the angle of dip is

A

$$\tan^{-1}\left(\dfrac{\sqrt{3}}{2}\right)$$

B

$$\tan^{-1}(\sqrt{6})$$

C

$$\tan^{-1}\left(\dfrac{\sqrt{2}}{3}\right)$$

D

$$\tan^{-1}\left(\dfrac{1}{\sqrt{2}}\right)$$