A capacitor is made of two square plates each of side 'a' making a very small angle $$\alpha$$ between them, as shown in figure. The capacitance will be close to:

A

$$\frac{\varepsilon_0 a^2}{d}\left(1 - \frac{\alpha a}{2d}\right)$$

B

$$\frac{\varepsilon_0 a^2}{d}\left(1 - \frac{\alpha a}{4d}\right)$$

C

$$\frac{\varepsilon_0 a^2}{d}\left(1 + \frac{\alpha a}{d}\right)$$

D

$$\frac{\varepsilon_0 a^2}{d}\left(1 - \frac{3\alpha a}{2d}\right)$$