In two successive years, 80 and 60 students of a school appeared at the final examination of which 60% and 80% passed respectively. The average rate of students passed (in percent) is

In 1st year ,number of students appeared = 80

Passing Percentage = 60%

Number of Students Passed in 1st year = $$\frac{60}{100}$$ x 80 = 48

In 2nd year number of students appeared = 60

passing percentage for 2nd year = 80%

Number of Students passed in 2nd year = $$\frac{80}{100}$$ x 60 = 48

Total students passed in 2 years = 48+48 = 96

average passing percentage rate in 2 years = $$\frac{96}{140}$$ x 100 = 68 $$\frac{4}{7}$$%