For on equation $$ax^2 + bx^2 + cx + d = 0,$$ if its roots are $$\alpha, \beta and \gamma$$, then
I. $$\alpha + \beta + \gamma = \frac{c}{a}$$
II. $$\alpha \beta \gamma = d$$

Solution

$$ax^3 + bx^2 + cx + d = 0,$$ if its roots are $$\alpha, \beta and \gamma$$, then

$$\alpha+\beta+\gamma=\frac{-b}{a}$$

$$(\alpha \beta)+(\beta \gamma)+(\gamma \alpha)=\frac{c}{a}$$

$$\alpha \beta \gamma=\frac{-d}{a}$$

Thus, neither of the statements is true.

=> Ans - (D)

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For on equation $$ax^2 + bx^2 + cx + d = 0,$$ if its roots are $$\alpha, \beta and \gamma$$, thenI. $$\alpha + \beta + \gamma = \frac{c}{a}$$II. $$\alpha \beta \gamma = d$$