RPF 10 Jan 2019

Question 108

When the article sold at the rate of Rs.1220 earned a profit of 11% more than that of the loss incurred when the same article sold at the rate of Rs.798. Find the Cost price of the article.


Let cost price of the article = Rs. $$x$$

Loss = Rs. $$(x-798)$$

Profit = Rs. $$(1220-x)$$

According to ques, => $$\frac{P-L}{L}\times100=11$$

=> $$\frac{(1220-x)-(x-798)}{(x-798)}\times100=11$$

=> $$\frac{2018-2x}{x-798}=\frac{11}{100}$$

=> $$11x-8778=201800-200x$$

=> $$11x+200x=201800+8778=210578$$

=> $$x=\frac{210578}{211}=998$$

$$\therefore$$ Cost price = Rs. 998

=> Ans - (C)

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