RPF 10 Jan 2019

Question 108

When the article sold at the rate of Rs.1220 earned a profit of 11% more than that of the loss incurred when the same article sold at the rate of Rs.798. Find the Cost price of the article.

Solution

Let cost price of the article = Rs. $$x$$

Loss = Rs. $$(x-798)$$

Profit = Rs. $$(1220-x)$$

According to ques, => $$\frac{P-L}{L}\times100=11$$

=> $$\frac{(1220-x)-(x-798)}{(x-798)}\times100=11$$

=> $$\frac{2018-2x}{x-798}=\frac{11}{100}$$

=> $$11x-8778=201800-200x$$

=> $$11x+200x=201800+8778=210578$$

=> $$x=\frac{210578}{211}=998$$

$$\therefore$$ Cost price = Rs. 998

=> Ans - (C)


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