Question 108
Chords AB and CD of a circle intersect at E and are perpendicular to each other. Segments AE, EB and ED are of lengths 2 cm, 6 cm and 3 cm respectively. Then the length of the diameter of the circle in cm is
Solution
AE = 2 cm
EB = 6 cm
ED = 3 cm
=> AE * EB = DE * EC
=> EC = $$\frac{2 * 6}{3}$$ = 4 cm
=> Diameter = $$\sqrt{7^2 + 4^2} = \sqrt{49 + 16}$$
= $$\sqrt{65}$$ cm
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