Chords AB and CD of a circle intersect at E and are perpendicular to each other. Segments AE, EB and ED are of lengths 2 cm, 6 cm and 3 cm respectively. Then the length of the diameter of the circle in cm is

A

$$\sqrt{65}$$

B

$$\frac{1}{2}\sqrt{65}$$

C

$$65$$

D

$$\frac{65}{2}$$