Question 105
A chord of length 30 cm is at a distance of 8 cm from the centre of a circle. The radius of the circle is:
Solution
Given : AC = 30 cm and OB = 8 cm
To find : OC = ?
Solution : AB = $$\frac{AC}{2}$$ = 15 cm
In right $$\triangle$$OBC
=> OC = $$\sqrt{(OB)^2 + (BC)^2}$$
=> OC = $$\sqrt{8^2 + 15^2}$$ = $$\sqrt{64 + 225}$$
=> OC = $$\sqrt{289}$$ = 17 cm
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