Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 105
A chord of length 30 cm is at a distance of 8 cm from the centre of a circle. The radius of the circle is:
Solution
Given : AC = 30 cm and OB = 8 cm
To find : OC = ?
Solution : AB = $$\frac{AC}{2}$$ = 15 cm
In right $$\triangle$$OBC
=> OC = $$\sqrt{(OB)^2 + (BC)^2}$$
=> OC = $$\sqrt{8^2 + 15^2}$$ = $$\sqrt{64 + 225}$$
=> OC = $$\sqrt{289}$$ = 17 cm
Video Solution
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
