A man buys 3 cows and 8 goats in 47,200. Instead if he would have bought 8 cows and 3 goats, he had to pay 53,000 more. Cost of one cow is
Let cost of 1 cow = $$x$$ and cost of 1 goat = $$y$$
=> $$3x + 8y = 47200$$
and $$8x + 3y = 100200 $$
=> Adding the above two equations, we get : $$11x + 11y = 147400 $$
=> $$x + y = 13400$$ -------Eqn (1)
=> Subtracting those, we get : $$5x - 5y = 53000$$
=> $$x - y = 10600$$ --------Eqn (2)
Now, adding eqns (1) & (2), we get
=> $$2x = 24000$$
=> $$x = 12000$$
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