Sign in
Please select an account to continue using cracku.in
↓ →
Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
The LCM of 12, 15 20,24, 30 = 120
the greatest of 6 digit = 999999
Dividing 999999 by 120 we get 39 as the remainder
Hence the 6 digit number divisible by 120 is (999999-39)
= 999960
Since 12-8=4 , 15-11 = 4, 20-16=4, 24-20= 4, 30-26 = 4
then reminder is each case is =4 less then the divior
Hence Requried number
999960-4 = 999956 Ans
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
