Question 103
Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
Solution
The LCM of 12, 15 20,24, 30 = 120
the greatest of 6 digit = 999999
Dividing 999999 by 120 we get 39 as the remainder
Hence the 6 digit number divisible by 120 is (999999-39)
= 999960Â
Since 12-8=4 , 15-11 = 4, 20-16=4, 24-20= 4, 30-26 = 4Â
then reminder is each case is =4 less then the diviorÂ
Hence Requried numberÂ
999960-4 = 999956 AnsÂ
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