Pipes A and can fill an empty tank in 6 and 8 hours respectively, while pipe C can empty the full tank in 10 hours. If all three pipes are opened together, then the tank will get filled in:
Pipe A Capacity in 1 hours = $$\dfrac{1}{6}$$
Pipe B Capacity in 1 hour = $$ \dfrac{1}{8}$$
Pipe C capacity in 1 hour = $$ - \dfrac{1}{10} $$
So if all Pipe are opened together thenÂ
$$ \dfrac{1}{6}+\dfrac{1}{8}-\dfrac{1}{10}$$
$$\Rightarrow \dfrac{20+15-12}{120}$$
$$\Rightarrow \dfrac{23}{120}$$
Time Taken = $$\dfrac{120}{23}$$
$$\Rightarrow 5 \dfrac{5}{23}$$ hours AnsÂ
Create a FREE account and get: