SSC JE Electrical Engineering 3rd March 2017 Shift-1

100

500

1000

1500

More

Less

Half

Same

$$ R = \left( \frac{1}{R1} \right) + \left( \frac{1}{R2} \right) + .... + \left( \frac{1}{Rn} \right)$$

$$ \frac {1} {R} = \left( \frac{1}{R1} \right) + \left( \frac{1}{R2} \right) + .... + \left( \frac{1}{Rn} \right) $$

$$ \frac {1} {R} = R1 + R2 +... + Rn $$

$$ R = R1 + R2 +....+Rn $$

The total voltage is 24 V.

The total voltage is zero.

The arrangement can be loaded upto 10 A maximum.

The voltage sources connected in a parallel can supply a maximum current of 20 A.

is different at different given temperatures

is same at different given temperatures

increases as temperature is increased

remains always constant

the temperature should remain constant

ratio of $$\frac{V}{I}$$ should be constant

the temperature should vary

current should be proportional to voltage

Copper wire of 5 m and 2 mm$$^2$$

Copper wire of 1 m and 6 mm$$^2$$

Aluminium wire of 8 m and 1 mm$$^2$$

Aluminium wire of 1 m and 6 mm$$^2$$

1 ampere

0.5 ampere

0.2 ampere

Zero

Iron, aluminium and brass

Iron, cobalt and zinc

Iron, copper and nickel

Nickel, cobalt and steel

Strengthening of the magnetic field by using iron (permeability)

The part of the magnetization curve in which the change in magnetic field strength H causes a little change in the magnetic flux density B.

The losses during magnetization

In the region of saturation the elementary magnets are not yet arranged fully