SSC CHSL 4 July 2019 Shift-1

Instructions

For the following questions answer them individually

Question 61

The parallel sides of a trapezium are 20 cm and 10 cm and its non-parallel sides are equal to each other. If its area is 180 cm$$^2$$, then what is the length (in cm) of each non-parallel side ?

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Question 62

Incomes of A and B are in the ratio 5 : 3 and their expenditures are in the ratio 9 : 5. If income of A is twice the expenditure of B, then what is the ratio of savings of A and B?

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Question 63

A can do 40% of a work in 6 days and B can do 30% of the same work in 3 days. They started the work together but B left after 2 days and A continued to work. In how many days was the entire work completed?

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Question 64

A shopkeeper marks his goods at 25% above the cost price. He sells three-fourth of the goods at the marked price and the remaining at 40% discount on the marked price. His gain/loss percent is:

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Question 65

For $$0^\circ < \theta < 90^\circ$$, If $$\frac{\sec \theta(1 - \sin \theta)(\sec \theta + \tan \theta)}{(\sec \theta - \tan \theta)^2} = \frac{1 + k}{1 - k}$$, then k is equal to:

Video Solution
Instructions

The given Bar Graph presents the Revenue and Expenditure (in crores of Rupees) of a company during the five year period, 2014-2018.

Question 66

In which year the percentage increase in the revenue as compared to that in its preceding year is between 5% and 8% ?

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Question 67

The total expenditure of the company from 2016 to 2018 is what percentage (nearest to an integer) of the total revenue for the five year period ?

Video Solution
Instructions

For the following questions answer them individually

Question 68

$$\triangle$$ABC is a triangle, where $$\angle$$B is obtuse. AD is perpendicular on CB produced at D. If AB = 8cm, BC = 7 cm and BD = 4 cm, then AC is equal to:

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Question 69

If $$x + y + z = 3  and  xy + yz + zx = -18$$,then what is the value of $$x^3 + y^3 + z^3 - 3xyz = ?$$

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Question 70

For $$0^\circ < \theta < 90^\circ$$, if $$2 \cos^2 \theta = 3 \sin \theta$$, then the value of $$(\cosec^2 \theta - \cot^2 \theta + \cos^2 \theta)$$is equal to:

Video Solution
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