SSC CHSL 13th October 2020 Shift-1
For the following questions answer them individually
The value of $$\left(a^{\frac{2}{3}} + 2a^{\frac{1}{2}} + 3a^{\frac{1}{3}} + 2a^{\frac{1}{6}} + 1\right)\left(a^{\frac{1}{3}} - 2a^{\frac{1}{6}} + 1\right)-a^{\frac{1}{2}}\left(a^{\frac{1}{2}} - 2\right)$$, when a = 7, is:
If, $$2^{x + y - 2z} = 8^{8z - 5 - y};5^{4y - 6z} = 25^{y + z};3^{4x - 3z} = 9^{x + z}$$ then the value of $$2x + 3y + 5z$$ is:
In the following figure, if angles $$\angle ABC = 95^\circ \angle FED = 115^\circ$$ (not to scale). Then the angle $$\angle APC$$ is equal to:
If $$A = \left[\frac{3}{7} of 4\frac{1}{5} \div \frac{18}{25} + \frac{17}{24}\right]$$ of $$\left[\frac{289}{16} \div \left(\frac{3}{4} + \frac{2}{3}\right)^2\right]$$, then the value of 8A is:
The following graph shows the expenditure on education sector by Indian government for the years-2014-15 to 2019-20
If the government plans to increase the expenditure by 30% on the average of the expenditures in 2016-17, 2017-18, 2018-19, then the approximate amount(in billions of rupees) to be spent in 2020-21 is:
5 men and 8 women can complete a task in 34 days, whereas 4 men and 18 women can complete the same task in 28 days. In how many days can the same task be completed by 3 men and 5 women?
The value of $$\frac{1}{\left(9 - 4\sqrt{5}\right)^2} + \frac{1}{\left(9 + 4\sqrt{5}\right)^2}$$ is:
The value of $$\left[\frac{\sqrt{3} +2 \sin P}{1 - 2 \cos P}\right]^3 + \left[\frac{1 + 2 \cos P}{\sqrt{3} - 2 \sin P}\right]^3$$ is:
In the given figure, AD is bisector of angle $$\angle$$CAB and BD is bisector of angle $$\angle$$CBF. If the angle at C is 34$$^\circ$$, the angle $$\angle$$ADB is:
