Instructions

In each question, two equations I and II have been given. You have to solve these equations and give the appropriate answer

Question 96

I. $$p^2+13p+40=0$$
II. $$q^2+7q+12=0$$

Solution

$$p^2+13p+40=0$$ => (p + 8)(p + 5) = 0

So, p = -8 or -5

$$q^2+7q+12=0$$ => (q+3)(q+4) = 0

So, q = -3 or -4

So, q is certainly greater than p. Hence, c is the correct answer.

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I. $$p^2+13p+40=0$$II. $$q^2+7q+12=0$$