The average of 25 consecutive odd integers is 55. The highest of these integers is

The 25 consecutive odd integers will form an arithmetic progression with common difference, $$d = 2$$

Let the first term be $$a$$

Average of 25 integers = 55, => Sum = $$25 \times 55 = 1375$$

=> Sum of these integers = $$\frac{n}{2}[2a+(n-1)d] = 1375$$

=> $$\frac{25}{2}[2a + (24 \times 2)] = 1375$$

=> $$25(a+24)=1375$$

=> $$(a+24)=\frac{1375}{25}=55$$

=> $$a=55-24 = 31$$

$$\therefore$$ The highest integer or the 25th term, $$A_{25} = a + (25-1)d$$

= $$31 + (24 \times 2) = 31 + 48 = 79$$

=> Ans - (A)