Question 92

In a triangle, the length of the opposite side of the angle which measures 45° is 8√2 cm, what is the length of the side opposite to the angle which measures 90°?

Solution

In the given triangle, two angles are 90° and 45°, => Third angle = 45°

=> The given triangle is isosceles right angled triangle with measure of equal sides = 8√2 cm

Let length of hypotenuse = $$h$$ cm

=> $$h^2 = (8\sqrt{2})^2 + (8\sqrt{2})^2$$

=> $$h^2 = 128 + 128 = 256$$

=> $$h = \sqrt{256} = 16$$ cm

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