Question 91

A cylindrical capsule has hemispherical ends of the radii equal to radius of the cylindrical part. If length of the capsule is 40 m and radius 6 m, what is the total surface area of this capsule?

Solution

Radius = 6 m and length of whole capsule = 40 m

=> Height of cylindrical part = AB = 40 - 6 - 6 = 28 m

Total surface area of cylinder = Curved surface area of cylinder + 2 $$\times$$ Curved surface area of hemisphere

= $$(2\pi rh)+(2 \times 2\pi r^2)$$

= $$(2\pi r)(h+2r)$$

= $$(2 \times \frac{22}{7} \times 6)(28 + 2 \times 6)$$

= $$\frac{264}{7} \times 40$$

= $$1508.57$$ $$m^2$$

=> Ans - (C)

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