2017 SSC CGL 19 Aug Shift-2

Question 89

The 2nd and 8th term of an arithmetic progression are 17 and -1 respectively. What is the 14th term?

Solution

$$T_{2}$$ = a + d = 17-------(1)

$$T_{8}$$ = a + 7d = -1-------(2)

on solving (1) AND (2)

d = -3 & a = 20

$$T_{14}$$ = a + 13d = 20 + 13(-3) = -19

so the answer is option C.


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