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If $$x-y=7$$ and $$x + y = 13$$, then $$x^2 - y^2$$ is
Equation 1 : $$x - y = 7$$
Equation 2 : $$x + y = 13$$
Adding both equations, we get : $$2x = 7 + 13 = 20$$
=> $$x = \frac{20}{2} = 10$$
Substituting value of 'x' in equation 1, => $$y = 10 - 7 = 3$$
To find : $$x^2 - y^2 = (10^2 - 3^2)$$
= $$100 - 9 = 91$$
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