In a Rhombus ABCD, measure of angle CAB is 25°, what is the measure of angle ABC?

Given : ABCD is a rhombus and $$\angle$$ CAB = 25°

To find : $$\angle$$ ABC = ?

Solution : Diagonals of a rhombus bisect each other at 90° and also bisect the angles of the rhombus.

In $$\triangle$$ AOB

=> $$\angle$$ AOB + $$\angle$$ OBA + $$\angle$$ BAO = 180°

=> 90° + 25° + $$\angle$$ OBA = 180°

=> $$\angle$$ OBA = 180° - 115° = 65°

$$\therefore$$ $$\angle$$ ABC = $$2 \times$$ $$\angle$$ OBA

= $$2 \times 65 = 130$$°

=> Ans - (D)