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If the mean of the frequency distribution
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequency | 2 | 3 | $$x$$ | 5 | 4 |
Correct Answer: 151
Mean = 28. Frequency distribution:
| Class midpoint | 5 | 15 | 25 | 35 | 45 |
| Frequency | 2 | 3 | x | 5 | 4 |
$$\sum f = 14 + x$$
$$\sum fx = 10 + 45 + 25x + 175 + 180 = 410 + 25x$$
Mean: $$\frac{410 + 25x}{14 + x} = 28$$
$$410 + 25x = 392 + 28x$$
$$18 = 3x$$, $$x = 6$$
$$\sum f = 20$$, $$\sum fx = 560$$
$$\sum fx^2 = 2(25) + 3(225) + 6(625) + 5(1225) + 4(2025) = 50 + 675 + 3750 + 6125 + 8100 = 18700$$
Variance = $$\frac{\sum fx^2}{\sum f} - \left(\frac{\sum fx}{\sum f}\right)^2 = \frac{18700}{20} - 784 = 935 - 784 = 151$$
The variance is 151.
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