Question 86

Two fractions are such that their product is 9/10 and sum is 77/40. What are the two fractions.

Solution

Let the two numbers be x and y

=> $$x + y = \frac{77}{40}$$ and $$x.y = \frac{9}{10}$$

=> $$x(\frac{77}{40} - x) = \frac{9}{10}$$

=> $$x(\frac{77 - 40x}{40}) = \frac{9}{10}$$

=> $$77x - 40x^2 = 36$$

=> $$40x^2 - 77x + 36 = 0$$

=> $$40x^2 - 32x - 45x + 36 = 0$$

=> $$8x(5x - 4) - 9(5x - 4) = 0$$

=> $$(8x - 9) (5x - 4) = 0$$

=> $$x = \frac{9}{8} , \frac{4}{5}$$

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Two fractions are such that their product is ­9/10 and sum is ­77/40. What are the two fractions.