Of the 3 numbers whose average is 77, the first is 3/4 times the sum of other 2. The first number is
Let the three numbers be $$x,y,z$$
Average of three numbers = $$\frac{x + y + z}{3} = 77$$
=> $$x+y+z=77 \times 3 = 231$$
According to ques, => $$x = \frac{3}{4} \times (y + z)$$
=> $$x = \frac{3}{4} \times (231 - x)$$
=> $$4x = 693 - 3x$$
=> $$4x + 3x = 7x = 693$$
=> $$x = \frac{693}{7} = 99$$
=> Ans - (C)
Create a FREE account and get:
