Question 84

Of the 3 numbers whose average is 77, the first is 3/4 times the sum of other 2. The first number is

Solution

Let the three numbers be $$x,y,z$$

Average of three numbers = $$\frac{x + y + z}{3} = 77$$

=> $$x+y+z=77 \times 3 = 231$$

According to ques, => $$x = \frac{3}{4} \times (y + z)$$

=> $$x = \frac{3}{4} \times (231 - x)$$

=> $$4x = 693 - 3x$$

=> $$4x + 3x = 7x = 693$$

=> $$x = \frac{693}{7} = 99$$

=> Ans - (C)

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