A man invested $$\frac{1}{3}$$ of his capital at 7%, $$\frac{1}{4}$$ at 8% and the remaining at 10% rate of simple interest. If his annual income from interests is Rs. 561, the capital invested was
Let total capital be x
According to the question
$$ \frac{\frac{x}{3} \times 7 \times 1}{100} + \frac{\frac{x}{4} \times 8 \times 1}{100} + \frac{(1 - \frac{1}{3} - \frac{1}{4}) \times x \times 10}{100} = 561 $$
$$ \frac{7x}{3 \times 100} + \frac{8x}{4 \times 100} + \frac{5x \times 10}{12 \times 100} = 561 $$
On solving, x = 6600
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