D and E are points on the sides AB and AC respectively of $$\triangle ABC$$ such that DE is parallel to BC and AD : DB = 4 : 5, CD and BE intersect each other at F. Then the ratio of the areas of $$\triangle DEF$$ and $$\triangle CBF$$

A

16 : 25

B

16 : 81

C

81 : 16

D

4 : 9