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Question 81
In the following figure, ABCD is a square whose each side is 10cm long. Mangles AEC and AEFC are congruent. Point B’ is the mid-point of side EC. Find the area of AEFC (in sq. cm).
Solution
BC=10cm and AC=10cm
$$\therefore$$ EC=20cm
Area of $$\triangle$$ AEC will be equal to Area of $$\triangle$$ AEC.
Area of $$\triangle$$ AEC = $$\frac{1}{2} \times$$ EC $$\times$$ AB = $$\frac{1}{2} \times$$ 20 $$\times$$ 10 = 100
Area of AEFC= $$2\times$$ Area of $$\triangle$$ AEC = 2$$\times$$ 100 = 200
Hence Option E is the correct answer.
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