If 4 + 3x ≤ 6 + x and 3x + 5 > 2 + 2x; then x can take which of the following values?

Question 81

Solution

Expression 1 : 4 + 3x ≤ 6 + x

=> $$3x - x \leq 6 - 4$$ => $$2x \leq 2$$

=> $$x \leq \frac{2}{2}$$ => $$x \leq 1$$ --------------(i)

Expression 2 : 3x + 5 > 2 + 2x

=> $$3x - 2x $$ > $$ 2 - 5$$

=> $$x $$ > $$ -3$$ ------------(ii)

Combining inequalities (i) and (ii), we get : $$-3 $$ < $$ x \leq 1$$

Thus, $$x$$ can take values = -2,-1,0,1

=> Ans - (B)

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