If 4 + 3x ≤ 6 + x and 3x + 5 > 2 + 2x; then x can take which of the following values?
Expression 1 : 4 + 3x ≤ 6 + x
=> $$3x - x \leq 6 - 4$$ => $$2x \leq 2$$
=> $$x \leq \frac{2}{2}$$ => $$x \leq 1$$ --------------(i)
Expression 2 : 3x + 5 > 2 + 2x
=> $$3x - 2x $$ > $$ 2 - 5$$
=> $$x $$ > $$ -3$$ ------------(ii)
Combining inequalities (i) and (ii), we get : $$-3 $$ < $$ x \leq 1$$
Thus, $$x$$ can take values = -2,-1,0,1
=> Ans - (B)
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