$$\frac{(1 + tan^{2}A)cotA}{cosec^{2}A}$$is equal to
Expression : $$\frac{(1 + tan^{2}A)cotA}{cosec^{2}A}$$
$$\because (sec^2A-tan^2A=1)$$
= $$\frac{sec^2AcotA}{cosec^2A}$$
= $$\frac{1}{cos^2A}\frac{cosA}{sinA}\div\frac{1}{sin^2A}$$
= $$\frac{1}{sinAcosA}\div\frac{1}{sin^2A}$$
= $$\frac{1}{sinAcosA} \times sin^2A$$
= $$\frac{sinA}{cosA} = tanA$$
=> Ans - (B)
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