Sign in
Please select an account to continue using cracku.in
↓ →
The flight fare between two cities is increased in the ratio 9:11. What is the increase (in Rs) in the fare, if the original fare was Rs. 18,000?
$$\frac{original price}{price after increase} = \frac{9}{11}$$
$$\frac{18000}{price after increase} = \frac{9}{11}$$
price after increase = 22,000
price increase = 22,000 - 18,000 = 4000
So the answer is option C.
Was this solution helpful?
Create a FREE account and get:
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
91- 6303239042
