Question 80

The flight fare between two cities is increased in the ratio 9:11. What is the increase (in Rs) in the fare, if the original fare was Rs. 18,000?

Solution

$$\frac{original price}{price after increase} = \frac{9}{11}$$

$$\frac{18000}{price after increase} = \frac{9}{11}$$

price after increase = 22,000

price increase = 22,000 - 18,000 = 4000

So the answer is option C.

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