Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
For an adiabatic expansion of an ideal gas, the fractional change in its pressure is equal to (where $$\gamma$$ is the ratio of specific heats):
For an adiabatic process involving an ideal gas, we have $$PV^\gamma = \text{constant}$$.
Taking the differential of both sides: $$V^\gamma \, dP + P \cdot \gamma V^{\gamma - 1} \, dV = 0$$.
Dividing throughout by $$PV^\gamma$$: $$\frac{dP}{P} + \gamma \frac{dV}{V} = 0$$.
Therefore, the fractional change in pressure is $$\frac{dP}{P} = -\gamma \frac{dV}{V}$$.
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.