JEE (Advanced) 2017 Paper-1 Question 8

Question 8

A drop of liquid of radius $$R = 10^{-2} m$$ having surface tension $$S = \frac{0.1}{4 \pi} Nm^{-1}$$ divides itself into 𝐾 identical drops. In this process the total change in the surface energy $$\triangle U = 10^{-3} J$$. If $$K = 10^\alpha$$ then the value of $$\alpha$$ is

Correct Answer: 6

Create a FREE account and get:

  • Free JEE Advanced Previous Papers PDF
  • Take JEE Advanced paper tests


Register with


Boost your Prep!

Download App