[Solved] A drop of liquid of radius R = 10^{-2} m having surface tension S = \\frac{0.1}{4 \\pi} Nm^{-1} divides itself into 𝐾 identical drops. In this process the total change in the surface energy \\triangle U = 10^{-3} J. If K = 10^\\alpha then the value of \\alpha is - - JEE (Advanced) 2017 Paper-1