For an isosceles prism of angle 𝐴 and refractive index $$\mu$$, it is found that the angle of minimum deviation $$\delta_m = A$$. Which of the following options is/are correct?

For the angle of incidence $$i_1 = A$$, the ray inside the prism is parallel to the base of the prism

For this prism, the refractive index $$\mu$$ and the angle of prism 𝐴 are related as $$A = \frac{1}{2} \cos^{-1}\left(\frac{\mu}{2}\right)$$

At minimum deviation, the incident angle $$i_1$$ and the refracting angle $$r_1$$ at the first refracting surface are related by $$r_1 = (i_1/2)$$

For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is $$i_1 = \sin^{-1} \left[\sin A \sqrt{4 \cos^2 \frac{A}{2} - 1} - \cos A\right]$$